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Chemistry Dimensional Analysis Problem?
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3 Responses to Chemistry Dimensional Analysis Problem?
15.0mL x 19.2gAu/1mL = 288g Au
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A key concept to this question is that 1 mL = 1 cm^3. From here you do two things.
1. Solve the equation for density (D=m/V) for m (mass)
D=m/V –> Multiply by V
DV=m
2. Convert the volume into a unit used in the density
15.0mL * 1cm^3 = 15.0 cm^3
———– ———–
…………….1mL
(Note that mL is on the top and bottom of the fraction bar thus it cancels. )
Now insert the Volume and Density values into the equation
Keep in mind that 19.2 g/cm^3 is the same as 19.2 g / 1 cm^3
m=DV
m = 19.2 g * 15.0cm^3 = 288 g
…….———
…….1 cm^3
(Note that cm^3 is on the top and bottom of the fraction bar thus it cancels. )
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Density = Mass/ Volume
or
Mass = Density X Volume
= 19.2 g/cm^3 X 15.0 ml
= 288 g (Answer)
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